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.15x^2-8x-150=0
a = .15; b = -8; c = -150;
Δ = b2-4ac
Δ = -82-4·.15·(-150)
Δ = 154
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{154}}{2*.15}=\frac{8-\sqrt{154}}{0.3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{154}}{2*.15}=\frac{8+\sqrt{154}}{0.3} $
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